IBPS SO Prelims Exam Model Paper 5

I. x2 – 25x + 150 = 0
⇒ x2 – 10x – 15x + 150 = 0
⇒ x(x – 10) – 15 (x – 10) = 0
⇒ (x – 10) (x – 15) = 0
⇒ x = 10, 15
II. y2 – 18y + 81 = 0
⇒ y2 – 9y – 9y + 81 = 0
⇒ y (y – 9) – 9 (y – 9) = 0
⇒ (y – 9) (y – 9) = 0
⇒ y = 9, 9Hence x > y