IBPS SO Prelims Exam Model Paper 5

I. x2 – 54x + 560 = 0
⇒ x2 – 40x – 14x + 560 = 0
⇒ x (x – 40) – 14 (x – 40) = 0
⇒ (x – 40) (x – 14) = 0
⇒ x = 40, 14
II. y2 – 22y + 121 = 0
⇒ y2 – 11y – 11y + 121 = 0
⇒ y (y – 11) – 11 (y – 11) = 0
⇒ (y – 11) (y – 11) = 0
⇒ y = 11, 11Hence x > y