If (13^2 – 5^2)^{3\/2} = 6^3 \times A, then the value of A is:

CTET 2 Math and Science Sep 2016 Paper

Question : 44 of 150

Marks: +1, -0

(13^2 – 5^2)^{3\/2} = 6^3 × A

, then the value of A is:

Solution:

Consider the following,

(13^{2}-5^{2})^{\;\;{3}/{2}}=[(13-5)(13+5)]^{\;\;{3}/{2}}

=[8×18]^{\;\;{3}/{2}}

=[(2×2×2×2×3×3)^{\;\;{1}/{2}}]^{3}

=[2×2×3]^{3}

(13^{2}-5^{2})^{\;\;{3}/{2}}=6^{2}×2^{3}

Now,compare with

(13^{2}-5^{2})^{\;\;{3}/{2}}=6^{2}×{A}

Go to Question:

Prev Question

Next Question