The reciprocal of [( \frac{3}{8})^{-2}\times( \frac{-4}{5})^{-3}] is:

( \frac{8}{3})^{2}\times( \frac{5}{-4})^{3}

CTET 2 Math and Science Sep 2016 Paper

Question : 43 of 150

Marks: +1, -0

The reciprocal of

[(\;\;{3}/{8})^{-2}×(\;\;{-4}/{5})^{-3}]

is:

Solution:

[(\;\;{3}/{8})^{-2}×(-\;\;{4}/{5})^{-3}]=[(\;\;{8}/{3})^{2}×(-\;\;{5}/{4})^{3}]

=[\;\;{8}/{3}×\;\;{8}/{3}×(-\;\;{5}/{4})(-\;\;{5}/{4})(-\;\;{5}/{4})]

=-125/9

Now, the required reciprocal of

[(\;\;{3}/{8})^{-2}×(-\;\;{4}/{5})^{-3}]

\;\;{1}/{(-\;\;{125}/{9})}=-\;\;{9}/{125}

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