CTET 2 Math and Science Feb 2016 Paper

Question : 44 of 120

Marks: +1, -0

ABCD is a quadrilateral in which BD = 40 cm. The lengths of the perpendiculars drawn from the opposite vertices on BD are 16 cm and 12 cm. The area of the quadrilateral (in

cm^2

) is

Validate

Solution:

Area of quadrilateral

=\;\;{1}/{2}×{BD}×({P}_{1}+{P}_{2})

=\;\;{1}/{2}×40×(16+12)=\;\;{1}/{2}×40×28=560

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