If a*b=a^2+b^2 and a.b=a^2–b^2 , the value of (5*2).25 is

CTET 2 Math and Science 2011 Paper

Question : 32 of 120

Marks: +1, -0

a*b=a^2+b^2

and

a.b=a^2–b^2

, the value of

(5*2).25

Solution:

Let

a*b=a^{2}+b^{2},a⋅b=a^{2}-b^{2}

Consider

(5*2).25=[25+4].25=29.25

=(29)^{2}-(25)^{2}

=(29-25)(29+25)

=4(54)=216

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