CTET 2 Math and Science 2011 Paper

Question : 33 of 120

Marks: +1, -0

If a, b and c are three natural numbers in ascending order, then

$c^{2}-a^{2}>b$
$c^{2}-a^{2}=b^{2}$
${c}^{2}-{a}^{2}<{b}^{2}$
$c^{2}+b^{2}=a^{2}$

Solution:

let

a=1,b=2,c=3

be three natural numbers suchthat

a < b < c

Now,

c^{2}-a^{2}=9-1=8

Consider,option (a) LHS = 8, RHS = 2
LHS > RHS
option (b) : LHS = 8, RHS = 4
LHS ≠ RHS
option (c) : LHS = 8 , RHS = 4
LHS ≮ RHS
option (d) : LHS = 9 + 4 = 13
RHS = 1
LHS ≠ RHS

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