AP ICET 2019 Shift 2 Paper

Question : 148 of 200

Marks: +1, -0

Bag

B_1

contains 4 white and 2 black balls. Bag

B_2

contains 3 white and 4 black balls. A bag is drawn at random and a ball is chosen at random from it. Then the probability that the ball drawn is white, is

$3/{14}$
$2/7$
${23}/{42}$
${23}/{41}$

Validate

Solution:

Required Probability

{1}/{2}× \;{4}/{6}+{1}/{2} ×{3}/{7}={1}/{3}+\;{3}/{14}

={14+9}/{42}=\;{23}/{42}

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