AP ICET 2017 Shift 1 Paper

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Question : 123 of 200

Marks: +1, -0

The remainder when

3x^{4}+16x^{3}+4x^{2}+2x+5

id divided by

2x-1

is

$123/16$
$135/16$
$141/16$
$147/16$

Solution:

Given :

f(x)=3x^4+16x^3+4x^2+2x+5

x-1=0⇒x={1}/{2}

{∴f({1}/{2})=3({1}/{2})^{4}+16({1}/{2})^{3}+4({1}/{2})^{2}+2({1}/{2})+5}

{{3}/{16}+2+1+1+5={3}/{16}+9={147}/{16}}

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