∫ {x-1}/{(x+1)\sqrt{x^3+x^2+x} dx =

Correct Answer is : 2 Tan−1(√1+x+x2x) + c

2 Tan^{-1} (\sqrt{{1+x+x^2}/x}) + c

Tan^{-1} (\sqrt{{1+x+x^2}/x}) + c

Tan^{-1} (\sqrt{x/{1+x+x^2}) + c

Tan^{-1} (\sqrt{{1+x^2}/x}) + c

AP EAMCET Engineering 20 Apr 2019 Shift 1 Paper

Section: Mathematics

Question : 72 of 160

Marks: +1, -0

∫

x−1

(x+1)√x3+x2+x

dx =

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