AP EAMCET Engineering 20 Apr 2019 Shift 1 Paper

Section: Mathematics

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Question : 73 of 160

Marks: +1, -0

If I (x) = ∫ x2(log‌x)2 dx and 1 (1) = 0 , then I (x) =

x3
18
[8(log‌x)2−3‌log‌x]+
7
18
x3
27
[9(log‌x)2+6‌log‌x]−
2
27
x3
27
[9(log‌x)2−6‌log‌x+2]−
2
27
x3
27
[9(log‌x)2−6‌log‌x−2]+
2
27

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