The standard emf of the cell (E^\circ_{\text{cell }} and equilibrium constant (K_{{eq}}) of the following reaction of 298 {K} {Cd}^{2+}+4 {NH}_{3} \⇌ {Cd}({NH}_{3})_{4}^{2+}

Correct Answer is : E°cell =0.21V,Keq=126×107

E^\circ_{\text{cell }} =1.0 {V}, K_{{eq}}=126 \\times10^{7}

E^\circ_{\text{cell }} =0.21 {V}, K_{{eq}}=126 \\times10^{7}

E^\circ_{\text{cell }} =1.0 {V}, K_{{eq}}=6.60 \\times10^{33}

E^\circ_{\text{cell }} =0.21 {V}, K_{{eq}}=6.60 \\times10^{33}

AMU Engineering 2018 solved paper Solved Paper

Section: Chemistry

Question : 90 of 150

Marks: +1, -0

The standard emf of the cell (E°cell and equilibrium constant (Keq) of the following reaction of 298K
Cd2++4NH3⇌Cd(NH3)42+

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