The reaction quotient (Q) for the reduction of {O}_{2} to {H}_{2} {O} in acid solution, {O}_{2}(g)+4 {H}^{+}(a q)+4 e^{-} \\to2 {H}_{2} {O}(l) is, [ where, \\alpha_{{H}^{+}}= activity of {H}^{+}, p_{O_{2}}= pressure of {O}_{2} when it is present in the reaction, p^\circ= pressure of {O}_{2} at standard state ] .

Correct Answer is : Q=p°αH+4+pO2

Q={p^\circ}/{\\alpha_{H^{+}}^{4}+p_{O_{2}}}

Q={P_{{O}_{2}}}/{\\alpha_{{H}^{+}}^{4}+p^\circ}

Q={\\alpha_{H^{+}}^{4}+P_{O_{2}}}/{p^\circ}

Q={\\alpha_{H^{+}}^{4}+p^\circ}/{p_{O_{2}}}

AMU Engineering 2018 solved paper Solved Paper

Section: Chemistry

Question : 89 of 150

Marks: +1, -0

The reaction quotient (Q) for the reduction of O2 to H2O in acid solution,
O2(g)+4H+(aq)+4e−→2H2O(l) is,
[ where, αH+= activity of H+,pO2= pressure of O2 when it is present in the reaction, p°= pressure of O2 at standard state ].

Q=
p°
αH+4+pO2
Q=
PO2
αH+4+p°
Q=
αH+4+PO2
p°
Q=
αH+4+p°
pO2

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