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Question : 91 of 150
Marks:
+1,
-0
Solution:
Degree of dissociation
(α)= Given
ΛmC=60ohm−1cm2eq−1 Λ°=400ohm−1cm2eq−1 On putting the values,
α==0.15 Concentration of
H+ in the solution will be
cα, where
C=0.002M ∴[H+]=(0.002×0.15)M=0.0003 Now,
pH=log[H+] =−log(0.0003) =3.52
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