Xavier Aptitude Test 2015 Paper

Question : 58 of 113

Marks: +1, -0

Product M is produced by mixing chemical X and chemical Y in the ratio of 5:4. Chemical X is prepared by mixing two raw materials, A and B, in the ratio of 1:3. Chemical Y is prepared by mixing raw materials, B and C, in the ratio of 2:1. Then the final mixture is prepared by mixing 864 units of product M with water. If the concentration of the raw material B in the final mixture is 50%, how much water had been added to product M ?

328 units
368 units
392 units
616 units
None of the above

Validate

Solution:

(b)

Fraction of

\mathrm{B}

in Product

{M}= {5}/{9} ×{3}/{4}+ {4}/{9} ×{2}/{3}=\ {77}/{108}

In 864 units of Product

\ {M}

, amount of

{B}=864 \×{77}/{108}=616

units
In the final mixture 50% is B.
Therefore, amount of final mixture
= 616 × 2 = 1232 units.
Amount of water added = 1232 – 864 = 368 units.

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