UPSEE Solved Model Paper 1

At resonance RLC circuit become pure resistive circuit and current in the circuit is given by-
i =

VR

R

{VR = potential difference across resistor}
i =

30

60

= 0.5 ampere
Also,
Potential drop across inductor
VL = iXL
VL = iωL
⇒ L =

VL

iω

=

20

0.5×2000

= 20 mH
At resonance,
ωL =

1

ωC

⇒ C =

1

ω2L

=

1

(2000)2×(20×10−2)

= 12.5 µF