UPSEE Solved Model Paper 1

Image distance 'v' from lens (After refraction from lens only)

1

v

−

1

u

=

1

f

(𝑓 = 20cm, 𝑢 = −40cm)
⇒

1

v

=

1

f

+

1

u

1

v

=

1

20

+(−

1

40

)
v = 40 cm
But there is a glass plate so shift in image (I I') = t(1−

1

µ

)
= 3(1−

1

3 2

)
= 1cm
So, distance of image from lens
= 40 + 1
= 41cm
Distance from glass plate = 41 - 10 = 31 cm