TS Police Constable Telugu Model Paper 9

Question : 60 of 200

Marks: +1, -0

\log_{343}^{49}

విలువ

Solution:

\log_{343}^{49}=1/{\log_{49}^{343}}=1/{\log_{7^2}^{7^3}}

={\log_{7}^{7^2}}/{\log_{7}^{7^3}}={2\log_{7}^7}/{3\log_{7}^7}=2/3

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