\sqrt(\x^2-2\x-15)(\x^2-5\x-24)(\x^2-13\x+40)=

Correct Answer is : (x+3)(x−5)(x−8)

TS ICET 27-July-2022 Shift-2 Solved Paper

Question : 119 of 200

Marks: +1, -0

√(\x^2-2\x-15)(\x^2-5\x-24)(\x^2-13\x+40)=

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