If \frac{48}{\x+\y}-\frac{6}{\x-\y}=10 and \frac{15}{\x+\y}+\frac{4}{\x-\y}=9, then (\x, \y)=

TS ICET 27-July-2022 Shift-2 Solved Paper

Question : 118 of 200

Marks: +1, -0

{48}/{\x+\y}-{6}/{\x-\y}=10

and

{15}/{\x+\y}+{4}/{\x-\y}=9

, then

(\x, \y)=

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