TS ICET 24 May 2019 Shift 1 Paper

Question : 136 of 200

Marks: +1, -0

In a triangle ABC , ∠A = ∠B = ∠C. The bisectors of the angles ∠B and ∠C interect at D. Then ∠BDC =

Solution:

∠ A=∠ B=∠ C=60^{∘}

And

∠DBC=30°

∴ ∠ BDC =180-(30^{∘}+30^{∘})

=120^{∘}

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