TS ICET 24 May 2019 Shift 1 Paper

Question : 118 of 200

Marks: +1, -0

If sin θ =

5/{13}

and θ is not in the first quadrant, then sec θ + tan θ =

Solution:

\sin θ=\;{5}/{13} θ ∉ Q_{1} ⇒ θ ∈Q_{2}

\sec θ=\;{-13}/{12}

\tan θ=\;{-5}/{12}

\secθ+\tan θ=\;{-13}/{12}-\;{5}/{12}=\;{-18}/{12}

=\;{-3}/{2}

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