x = 3-\sqrt5 ⇒ \x^2 + 4 =

TS ICET 24 May 2018 Shift 1 Paper

Question : 81 of 200

Marks: +1, -0

x = 3-√5

⇒

\x^2 + 4 =

Solution:

Given

x=3-√{5} ⇒ x-3=-√{5}

Squaring on both sides

x^{2}-6 x+9=5

⇒ x^{2}+4=6 x

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