TS ICET 23 May 2019 Shift 2 Paper

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Question : 130 of 200

Marks: +1, -0

The coefficient of

x^5

in the expansion of

({4x}/5-5/{2x})^9

is

${9×2^{14}}/5^6$
${9×2^{15}}/5^6$
${9×2^{16}}/5^5$
${9×2^{14}}/5^5$

Solution:

Let

t_{r + 1}

be the term containing

x^5

Then

r=\;{n p-m}/{p+q}

Here n = 9, p = 1, q = 1, m = 5

∴ T_{2+1}={ }^{9} C_{2} ⋅(\;{4}/{5})^{7}(\;{-5}/{2})^{2} ⋅ x^{5}

⇒ 9 ⋅ \;{2^{14}}/{5^{5}}

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