TS ICET 23 May 2018 Shift 1 Paper

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Question : 80 of 200

Marks: +1, -0

If

√x + √ y =13

and

√x - √y =7

then

√{xy

=

30
$√{20$
$√{30$
$3√2$

Solution:

Given

√{x}+√{y}=13

→ (1) and

√{x}-√{y}=7

→ (2)
From (1) + (2)

⇒ 2√x = 20⇒√x = 10

From (1) - (2)

⇒2√y=6⇒√y=3

Hence

√{xy}=10×3=30

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