If □ is defined by a□b = {a-b}/{a+b , ⋄ by a⋄b = {a+b}/{a-b, → is defined by a→b = ab, then, \frac{(55 □5)\to(77⋄7)}{(2 □3)\to(4⋄5)} =

TS ICET 23 May 2018 Shift 1 Paper

Question : 73 of 200

Marks: +1, -0

If □ is defined by a□b =

{a-b}/{a+b

, ⋄ by a⋄b =

{a+b}/{a-b

, → is defined by a→b = ab, then,

{(55 □5)→(77⋄7)}/{(2 □3)→(4⋄5)}

Solution:

a□b={a-b}/{a+b},a◇b={a+b}/{a-b},a→b=a b

{(55□5) →(77◇7)}/{(2 □ 3) →(4◇5)}

\;{[{55-5}/{55+5}] →[{77+7}/{77-7}]}/{[\;{2-3}/{2+3}] →[\;{4+5}/{4-5}]}

\;{[{50}/{60}] →[{84}/{70}]}/{[\;{-1}/{5}] →[\;{-9}/{1}]}

\;{\;{50}/{60} × {84}/{70}}/{{9}/{5}}=\;{5}/{9}

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