TS ICET 23 May 2018 Shift 1 Paper

Question : 119 of 200

Marks: +1, -0

(1 + tan 17°) (1 + tan 28°) =

Solution:

\tan (27+18) =\tan (45) = 1

\;{\tan 27+\tan 18}/{1-\tan 27 \tan 18}=1

⇒ \tan (27)+\tan (18)=1-\tan (27) \tan (18)

⇒ \tan (27)+\tan (18)+\tan (27) \tan (18)=1

Required answer

(1+\tan(27))(1+\tan(18))

= 1 + \tan(27) + \tan(18)+\tan(27)\tan(18)

=1+1=2

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