TS ICET 2017 Question Paper with Solutions for online practice

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Question : 132 of 200

Marks: +1, -0

A =

[\table 1,2,2;2,1,2;2,2,1]

⇒

A^2

- 3A - 4I =

O
I
A + I
A - I

Solution:

Given

A=[\table1,2,2;2,1,2;2,2,1]

∴A^2=[\table9,8,8;8,9,8;8,8,9]

A^2-3A-4I=[\table (9-3-4),8-6,8-6;8-6,(9-3-4),8-6;8-6,8-6,(9-3-4)]

[\table2,2,2;2,2,2;2,2,2]=[\table 1,2,2;2,1,2;2,2,1]+[\table1,0,0;0,1,0;0,0,1]=A+I

Hence, LHS = RHS

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