TS ICET 2015 Question Paper with Solutions for online practice

Question : 87 of 200

Marks: +1, -0

Three numbers are in the ratio 1:2:3 the sum of the cubes of them is 36. The smallest number among them is

Solution:

Let the three numbers be k, 2k, 3k

⇒k^3+(2k)^3+(3k)^3=36

⇒36k^3=36

⇒k^3=1

⇒k=1

The smallest no. is 1.

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