TS ICET 2015 Question Paper with Solutions for online practice

Total no. of outcomes = Total no. of balls = 18
No. of favorable outcomes = No. of green or black balls $=5+6=11$
∴ Required probability $=\frac{11}{18}$
Aliter: p(green) $=\frac{5}{8}$,p(black)$=\frac{6}{18}$
∴ The probability that the chosen ball is either green or black
= p(green) + p(black) $=\frac{5}{18}+\frac{6}{18}=\frac{11}{18}$