The general solution of the differential equation \frac{d y}{d x}= \sin (x-y)+\cos (x-y) is [TG EAPCET 13 May 2023 Shift 1]

Correct Answer is : log|tan(x−y)2−1tan(x−y)2|=x+c

\log {| \binom{\tan \frac{(x-y)}{2}+1}/{\tan \frac{(x-y)}{2}} |}=x+c

\log {| \binom{\tan \frac{(x-y)}{2}-1}/{\tan \frac{(x-y)}{2}} |}=x+c

\log {| \frac{\tan (x-y)-1}{\tan (x-y)} |}=x+c

\log {| \frac{ \sin (x-y)+\cos (x-y)}{\cos (x-y)} |}=x+c

TS EAMCET Engineering 13 May 2023 Shift 1 Solved Paper

Section: Mathematics

Question : 79 of 160

Marks: +1, -0

The general solution of the differential equation ‌

=sin‌(x−y)+cos(x−y) is

[TG EAPCET 13 May 2023 Shift 1]

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