TS EAMCET Engineering 13 May 2023 Shift 1 Solved Paper

Section: Mathematics

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Question : 78 of 160

Marks: +1, -0

If A and B are arbitrary constants, then the differential equation having y=Aex+Bsin‌2x as its general solution is

[TG EAPCET 13 May 2023 Shift 1]

(cos‌2‌x−sin‌2x)‌
d2y
dx2
+(4sin‌2x)‌
dy
dx
−4(sin‌2x+cos‌2‌x)y=0
(cos‌2‌x+sin‌2x)‌
d2y
dx2
+(4sin‌2x)‌
dy
dx
−4(sin‌2x−cos‌2‌x)y=0
(cos‌2‌x−sin‌2x)‌
d2y
dx2
+(4sin‌2x)‌
dy
dx
+4(sin‌2x+cos‌2‌x)y=0
(sin‌2x−cos‌2‌x)‌
d2y
dx2
−(4sin‌2x)‌
dy
dx
−4(sin‌2x+cos‌2‌x)y=0

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