If 4+3 x-7 x^2 attains its maximum value M at x=\alpha and 5 x^2-2 x+1 attains its minimum value m at x=\beta, then {28( {\M}-\alpha)}/{5( {\m}+\beta)}= [TG EAPCET 9 May 2024 Shift 2]

TS EAMCET 9 May 2024 Shift 2 Solved Paper

Section: Mathematics

Question : 13 of 160

Marks: +1, -0

If 4+3x−7x2 attains its maximum value M at x=α and 5x2−2x+1 attains its minimum value m at x=β, then ‌

28(M−α)

5(m+β)

[TG EAPCET 9 May 2024 Shift 2]

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