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Question : 12 of 160
Marks:
+1,
-0
Solution:
Given
α is a root of the equation
‌‌=‌,‌ where ‌−‌<α<0‌∴‌=‌‌⇒‌=(‌)2‌⇒3600(α2−2α+1)=1681(2α2−5α+2)‌⇒238α2+1205α+238=0‌⇒238α2+1156α+49α+238=0‌⇒34α(7α+34)+7(7α+34)=0‌⇒(34α+7)(7α+34)=0‌⇒α=−‌,−‌‌∵−‌<α<0‌∴α=−‌
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