TS EAMCET 5 May 2018 Shift 1 Solved Paper

Section: Mathematics

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Question : 42 of 160

Marks: +1, -0

Let x ≠ 0 , |x| <

1

2

and f (x) = 1 + 2x + 4x2 + 8x3 + ... . Then f−1(x) =

x−1
2x
x−1
2
x−1
x
1 - 2x

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