TS EAMCET 5 May 2018 Shift 1 Solved Paper

The given function is,
X = {(

a	b
c	d

):a,b,c,d∊ℝ}
f(A)=det(A)
So,
f(x)=det(X)
=|

a	b
c	d

|
=ad−bc
For any real values of a, b, c and d, the matrix can be made, and, we get the pre-image of every real number. Thus, the function is onto.
But, for different values of a, b, c and d we get the same results to function. Thus, the function is not one-one.