TS EAMCET 5-Aug-2021 Shift 1 Question Paper

Given, acceleration of cars A and B is a1 and a2,
initial velocities of cars A and B are zero, final velocities of car A and B are v1 and v2, respectively.
Distance between cars A and B,s=50m
Net acceleration, a‌net ‌=4ms−2
By using second equation of motion,
v2−u2=2as
∴‌‌(v1−v2)2−0=2(a1−a2)s
⇒‌‌(v1−v2)2=2×4×50=400
⇒‌‌v1−v2=20ms−1