TS EAMCET 5-Aug-2021 Shift 1 Question Paper

Given, QV=kpTLα. . . (i)
where, V,p,T and L are volume, pressure, time and length respectively and dimensional formula of
‌[Q]=[ML−1T−1]
‌[k]=[M0L0T0]
As we know that, the dimensional formula of
‌[V]=[M0L3T0]
‌[p]=[ML−1T−2]
‌[T]=[M0L0T1]
‌[L]=[M0L1T0]α
Now, put the dimensional formula of [Q],[V],[k], [p],[T] and [L] in Eq. (i), we get ⇒‌‌[Q][V]=[k][p][T][L]α
⇒‌‌[M−1T−1][M0L3T0]=[M0L0T0][ML−1T−2]
[M0L0Tl][M0L1T0]α
⇒[ML2T−1]=[M0+1+0+0L0−1+0+αT0−2+1+0]
∴‌‌−1+α=2
⇒‌‌α=3