Let a^{-},b^{-},c^{-},d^{-} be four vectors such that a^{-} is perpendicular only to c^{-}. The vector b^{-} is parallel to (c^{-}-d^{-}), then c^{-} =

Correct Answer is : −d−(−a.−d−a.−b)−b

b^{-} - ({a^{-}.d^{-}}/{a^{-}.b^{-}}) d^{-}

d^{-} - ({a^{-}.d^{-}}/{a^{-}.b^{-}}) b^{-}

d^{-} + ({a^{-}.d^{-}}/{a^{-}.b^{-}}) b^{-}

b^{-} + ({a^{-}.d^{-}}/{a^{-}.b^{-}}) d^{-}

TS EAMCET 4-Aug-2021 Shift 2 Question Paper

Section: Mathematics

Question : 36 of 160

Marks: +1, -0

Let

−

be four vectors such that

−

is perpendicular only to

−

. The vector

−

is parallel to (

−

), then

−

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