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Question : 35 of 160
Marks:
+1,
-0
Solution:
a=2−+,b=2−3 a|c⇒a×c=0 a⟂b⇒a⋅b=0 Given,
‌‌b=c−d ⇒‌‌a⋅b=a⋅(c−d) ‌‌=a⋅c−a⋅d a⋅b‌‌=a⋅casa|c c‌‌=λa a⋅b‌‌=a⋅λa λ‌‌λ‌‌=‌=‌ c‌‌=‌a d‌‌=c−b ‌‌=‌a−b ∴‌‌‌ Now, ‌c+d‌‌=‌a−‌a−b ‌‌=‌a−b=‌(5a+3b)
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