TS EAMCET 2017 Code A Solved Paper

Consider the triangle as shown below
Angle A is calculated as
sin‌A=‌‌

√3k

2k

sin‌A=‌‌

√3

2

A= 60°
Angle C is calculated as,
sin‌C=‌‌

K

2K

sin‌C=‌‌

1

2

C= 30°
Angle B = 90°
Ratio of the angles is,
A : B : C = 30 : 60 : 90° = 1 : 2 : 3