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Question : 20 of 160
Marks:
+1,
-0
Solution:
Solve the integral as follows.
I=∫x4e2xdx=x4‌∫e2xdx−∫‌‌‌∫e2xdx⋅dx+C =‌‌−‌‌‌∫4x3e2xdx+C =‌‌−2[‌‌−∫‌‌dx]+C =‌‌−x3e2x+3[‌‌−‌‌‌∫2xe2xdx]+C =‌‌−x3e2x+‌‌x2e2x−3[‌‌−∫‌‌dx]+C =‌‌−x3e2x+‌‌x2e2x−‌‌xe2x+‌‌+C =‌‌[2x4−4x3+6x2−6x+3]+c
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