TS EAMCET 20-July-2022 Shift 1 Solved Paper

The given situation is shown below.Now, speed of bus in X to Y-direction observed by man=v−u
and speed of bus in Y to X-direction observed by man=v+u
Buses moves in either direction with equal speedv and at equal time intervals T. So, distance between buses coming from either direction is same.
So, speed × time = speed × time
(X to Y)(Y to X)
⇒‌(v−u)t1‌=(v+u)t2
⇒‌v(t1−t2)‌=u(t1+t2)
‌ or ‌‌u‌=‌

v(t1−t2)

t1+t2

Hence, distance D between any 2-buses is
D‌=(v−u)t1
‌=(v−‌

v(t1−t2)

t1+t2

)t1
‌=v(‌

t1+t2−t1+t2

t1+t2

)t1
D‌=v(‌

2t1t2

t1+t2

)
Hence, time interval between any 2-buses is
T‌=‌

‌ Distance ‌

‌ Speed ‌

‌=‌

D

v

=‌

2t1t2

t1+t2