TS EAMCET 20-July-2022 Shift 1 Solved Paper

Ball has same displacement H at t=2 s and t=10 sNow we use,
s=ut+‌1∕2at2
For t=2 s, (upward motion of ball)
H=u×2+‌1∕2(−9.8)×22
⇒‌‌H=2u−19.6...(i)
For t=10 s (downward motion of ball)
H=u×10+‌

1

2

(−9.8)×102
⇒‌‌H=10u−490.....(ii)
From Eqs. (i) and (ii), we have
10u−490‌=2u−19.6
⇒‌8u‌=470.4
⇒‌u‌=58.8m∕ s
Substituting u in Eq. (i) we get,
‌H=2×(58.8)−19.6
⇒‌‌:‌‌H=98m