TS EAMCET 19-July-2022 Shift 2 Solved Paper

Since, collision is head on, then particle A will continue moving along the same line as before the collision, but there will be a change in the magnitude of its velocity vector. Let particle A starts moving with velocity v1 and particle B with velocity v2 after collision, then from conservation of linear momentum,
mu=mv1+mv2
or
u=v1+v2.....(i)
From the given condition,
i.e
η=‌

‌ 1 2 mu2−( 1 2 mv12+ 1 2 mv22)

1 2 mu2

⇒‌‌η=1−‌

v12+v22

u2

⇒‌‌v12+v22=(1−η)u2.....(ii)
Now solving Eqs. (i) and (ii), we get v1=5m∕ s