TS EAMCET 19-July-2022 Shift 2 Solved Paper

The given situation is shown below.Radius of vertical circle, r=‌

AB

2

=2m
⇒AB= diameter =d=2×2=4m
Using the concept of conservation of energy, Total energy at point X= Total energy at point Y
Total energy at point X= Total energy at point Y.
⇒‌‌mgh+0‌=‌

1

2

mv2+0
h‌=‌

v2

2g

....(i)
Since, body just completes motion in vertical circle, hence v=√5gr.....(ii)
From Eqs. (i) and (ii), we get
h‌=‌

(√5gr)2

2g

=‌

5gr

2g

=‌

5r

2

‌=‌

5×2

2

=5m