TS EAMCET 19-July-2022 Shift 1 Solved Paper

Section: Mathematics

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Question : 57 of 160

Marks: +1, -0

The cartesian equation of the parabola x=−2+2t2,y=2+4t is

y2−8x−4y+12=0
y2−8x−4y−12=0
y2+8x−4y−12=0
y2−8x+4y−12=0

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