TS EAMCET 19-July-2022 Shift 1 Solved Paper

Statement I
Let P(x,y) be any point on parabola.
Distance from P to focus = Perpendicular distance from ? to direction
‌√(x−2)2+(y−3)2=‌

|x+2y+5|

√12+22

‌5(x2+y2−4x−6y+4+9)=x2+4y2
‌+25+4xy+20y+10x
‌4x2+y2−4xy−30x−50y+40=0
∴ Statement I is true.
Statement II
x2−4x+16y+52=0
x2−4x+4=−16y−48
(x−2)2=−16(y+3)
Comparison with X2=4aY, we get vertex (2,−3)
Equation of directrix is Y=a
y+3=4⇒y=1‌ or ‌y−1=0
∴ Statement II is wrong.