TS EAMCET 18-July-2022 Shift 1 Solved Paper

We know that, Prime numbers =2,3,5
Composite numbers =4,6.
Pairs of prime numbers on both the die in first throw
={(2,2),(2,3),(2,5),(3,2),(3,3),(3,5),
(5,2),(5,3),(5,5)}
⇒ Total pairs =9
Pairs of composite numbers on both the die in second throw
={(4,6),(4,4),(6,4),(6,6)}
∴ Required probability =‌

9

36

×‌

4

36

=‌

1

36