TS EAMCET 18-July-2022 Shift 1 Solved Paper

So, volume of cube having edge of length 5‌cm and all faces are painted
=53=125cm3
Let cube be divided into ' n ' small cubes of unit volume.
Volume of big cube =n× volume of unit volume cube
125=n×1⇒n=125
Now,
Number of cubes whose 3 faces are painted =8
Number of cubes whose 2 faces are painted =36
Number of cubes whose l face is painted =54
Number of cubes whose 0 face is painted
=125−(8+36+54)=27
∵ Required probability

=

3 faces painted cubes

‌ Cubes whose atleast one face is painted ‌

=‌

8

8+36+54

=‌

8

98

=‌

4

49